Sunday, October 11, 2009

PHYSICS HELP! hooks law, very easy?

a bungee cord needs to transfer 2.0x10^6J of E.


a 10 kg mass extends the bungee cord 1.3m.


what is the max extension in the bungee cord.





please i need the solution


the answer is 2.3x10^2m





thank you!

PHYSICS HELP! hooks law, very easy?
k = mg/L = 10*9.8/1.3 = 75.385 N/m





E = ½kX² → X = √(2E/k) = √(2*2E6/75.385) = 230.35 m



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